In A Trapeziod Where The Parellel Side Is 4cm And 6cm And Distance Is 7meters

IN A TRAPEZIOD WHERE THE PARELLEL SIDE IS 4CM AND 6CM AND DISTANCE IS 7METERS

Answer:

If you are asking the area, then the answer is 3500 $cm^2$ or 0.35 $m^2$ .

Step-by-step explanation:

The solution for this problem goes like this

$A = \frac{1}{2}(B_1+B_2)h\\A = \frac{1}{2}(4cm+6cm)(700cm)\\A = 3500cm^2$

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